[AccessD] OT: Friday entertainment

Scott Marcus marcus at tsstech.com
Fri Sep 23 13:24:28 CDT 2005


A Hitchhiker told me the answer is '42'.

Scott Marcus
IT Programmer
TSS Technologies Inc.
www.tss.com

-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Shamil
Salakhetdinov
Sent: Friday, September 23, 2005 11:30 AM
To: Access Developers discussion and problem solving
Subject: Re: [AccessD] OT: Friday entertainment

> Well, you _have_ a clue.
OK, I have it but I don't see it.

> You may wish to read my hint again ...
Yes, I did read it: "A hint: The requested item is the last one
possible" -
still no wise sparks in my braincells....

Maybe the answer is 44? - the last one possible two digits number if we
assume that 5 is a notation basis of the original sequence:

10 11 12 13 14  20  22  31  44

Even if the answer is correct - no clue why it's so....

Are the original numbers scancodes/codes for the core letters of keypad:
ASDFGHJKL? These are nine letters and nine numbers are in the requested
sequence - then hint works but still no clue how keypad letters
correspond
to the given numbers' sequence....

Maybe tomorrow I will give it another try if somebody else will not
solve it
before. No time on entertainment today, have to do some boring work...

Thanks,
Shamil

----- Original Message ----- 
From: "Gustav Brock" <Gustav at cactus.dk>
To: <accessd at databaseadvisors.com>
Sent: Friday, September 23, 2005 6:29 PM
Subject: Re: [AccessD] OT: Friday entertainment


> Hi Shamil
>
> Well, you _have_ a clue.
> You may wish to read my hint again ...
>
> A puzzle for me? Thanks! Will get to that later.
>
> /gustav
>
> >>> shamil at users.mns.ru 23-09-2005 15:27:25 >>>
> Gustav,
>
> One may guess the basis of notation isn't decimal and try the most
obvious
> 5, 7 and 16 as a notation basis and convert the sequence to the
numbers
> with decimal notation basis - then they will get:
>
>         10 11 12 13 14  20  22  31
>
> 5:     5     6   7    8   9  10  12  16
> 7:     7     8   9   10 11 14 16  22
> 16:  16  17 18  19 20 32 34  49
>
> No clue :(
>
> Stupid idea: total quantity of any used digit should be even or odd
> and the answer should be greater than the last number in the sequence
and
> the answer should have two digits?:
>
> Given:
> =====
>   0 -> 2
>   1 -> 7
>   2 -> 4
>   3 -> 2
>   4 -> 1
>
> With one additional number with two digits  the quantity of every used
digit
> can be made even. It can't be made odd.
>
> Target:
> =====
>   0 -> 2
>   1 -> 8
>   2 -> 4
>   3 -> 2
>   4 -> 2
>
> Answer: 41?
>
> It doesn't look like this answer deserve a a tasty chocolate but
anyway
for
> others to look for the right answer in other areas....
>
> Shamil
>
> P.S. My Friday puzzle to you Gustav :)
>
> What is the missing number:
>
> 10 11 12 13 14  20  22  (?) 31
>
>
> ----- Original Message ----- 
> From: "Gustav Brock" <Gustav at cactus.dk>
> To: <accessd at databaseadvisors.com>
> Sent: Friday, September 23, 2005 3:06 PM
> Subject: Re: [AccessD] OT: Friday entertainment
>
>
> > Hi all
> >
> > We still have this open:
> >
> > 3. What is the next number in this series:
> >   10 11 12 13 14 20 22 31 ?
> >
> > It's quite clever in fact. A true nerd thing suited for any
programmer.
> > A hint: The requested item is the last one possible ...(?!!)
> >
> > /gustav
>
>
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