[AccessD] Age calculation

Susan Harkins ssharkins at setel.com
Mon Jun 25 08:48:08 CDT 2007


I came up with this one years and years ago -- will it work for you?

Year(Now())-Year(date)+(DateSerial(Year(Now()),Month(date),Day(date))>Now())

Susan H. 

Hi Steve

Sorry, it still fails miserably for, say, these dates:

DOB = #2/29/1992#
AtDay = #2/28/1997#

returning 4 and not 5.

/gustav

>>> miscellany at mvps.org 23-06-2007 22:57 >>>
Hehe.  Answering my own question.  I wouldn't mind $5 for every time I have
used that expression over the last 12 years, on the assumption that I had it
licked.

And now I see the obvious - in the case of a 29 February birthday,
evaluating age on 28 February in a non leap year works correctly, but
evaluating age on 28 February during a leap year, it gives the wrong figure.

So, I have modified accordingly...

Age: DateDiff("yyyy",[DOB],[DateAt])+(Format([DOB]+(Format([DOB],"mmdd")
=Format([DateAt],"mmdd")="0229"),"mmdd")>Format([DateAt],"mmdd"))

Regards
Steve


Steve Schapel wrote:
> However, I can't find an example where the following does not work 
> correctly.  Can you?
> 
> Age: 
> DateDiff("yyyy",[DOB],[DateAt])+(Format([DOB]+(Format([DOB],"mmdd")
> ="0229"),"mmdd")>Format([DateAt],"mmdd"))
-- 


--
AccessD mailing list
AccessD at databaseadvisors.com
http://databaseadvisors.com/mailman/listinfo/accessd
Website: http://www.databaseadvisors.com

No virus found in this incoming message.
Checked by AVG Free Edition. 
Version: 7.5.472 / Virus Database: 269.9.1/857 - Release Date: 6/20/2007
2:18 PM
 




More information about the AccessD mailing list