[dba-Tech] The Three Doors Problem

Arthur Fuller artful at rogers.com
Fri Aug 26 18:57:56 CDT 2005


You missed the crucial element of the problem, John. The Host knows what is
behind all 3 doors, and thus NEVER removes the winning door. I attempted to
make this clear in the presentation of the problem, and I obviously failed
to do so. My apologies.

-----Original Message-----
From: dba-tech-bounces at databaseadvisors.com
[mailto:dba-tech-bounces at databaseadvisors.com] On Behalf Of Scott Marcus
Sent: August 26, 2005 9:56 AM
To: Discussion of Hardware and Software issues
Subject: RE: [dba-Tech] The Three Doors Problem

John,

The fact remains that when you picked the door, you had a 1/3 chance of
being correct. If the host removes a door (no matter which because if
the host removes the winning door your chance is 0%), the host just
increased your chances to being 2/3 correct.

Scott Marcus
IT Programmer
TSS Technologies Inc.
www.tss.com


-----Original Message-----
From: dba-tech-bounces at databaseadvisors.com
[mailto:dba-tech-bounces at databaseadvisors.com] On Behalf Of John W.
Colby
Sent: Friday, August 26, 2005 7:36 AM
To: 'Discussion of Hardware and Software issues'
Subject: RE: [dba-Tech] The Three Doors Problem

And it is exactly because of the "intentionally and knowingly taking
away
the non-winning door" that the logic works.  If the host "just picks a
door"
(which wasn't apparent from the original post) and the door "just
happens to
be not the prize", then the problem changes.  By the fact that that the
host
had knowledge of and intentionally chose a door with no prize, the
problem
does change, and I understand the answer.

By the way, the way you just worded it it still wouldn't make a
difference.
Only if you knowingly took away doors that you knew did not have a prize
would your answer be correct.  If you just randomly chose which doors to
eliminate then the problem is back to 50/50 because in fact, you may
very
well have eliminated the prize as well (in fact probably did).

>I open another door, and say, Had you selected door y, you would have
won a
dead catfish. 

No where does that imply that he intentionally chose a door with no
prize,
he just opened (picked at random) a remaining door, looked at the
contents,
and announced the contents of that door.

Not that I would have gotten the answer anyway, but I do understand that
by
his using his knowledge to pick a door with no prize he affected the
outcome.

John W. Colby
www.ColbyConsulting.com 

Contribute your unused CPU cycles to a good cause:
http://folding.stanford.edu/

-----Original Message-----
From: dba-tech-bounces at databaseadvisors.com
[mailto:dba-tech-bounces at databaseadvisors.com] On Behalf Of Scott Marcus
Sent: Friday, August 26, 2005 7:17 AM
To: Discussion of Hardware and Software issues
Subject: RE: [dba-Tech] The Three Doors Problem


John,

The problem with you logic is as follows... If there were 1,000,000
doors of
which only 1 had the prize and I took away all doors except yours and
another door, would you then switch? By your logic, your chance is
50/50.
Sorry, but I will switch every time.

Scott Marcus
IT Programmer
TSS Technologies Inc.
www.tss.com


-----Original Message-----
From: dba-tech-bounces at databaseadvisors.com
[mailto:dba-tech-bounces at databaseadvisors.com] On Behalf Of John W.
Colby
Sent: Thursday, August 25, 2005 10:44 PM
To: 'Discussion of Hardware and Software issues'
Subject: RE: [dba-Tech] The Three Doors Problem

LOL, but the answer is screwy.  Now take the example where TWO people
are
choosing doors simultaneously.  The third door is shown to NOT contain
the
prize.  Both people should swap by the logic of the puzzle, but one of
them
is still going to lose and the other win.  Each person (door) has a 50%
probability of winning.  Which one will win?  There is no way to predict
the
answer, each person has a 50% probability of winning the prize.

The logic SOUNDS good but is screwy.  Each door has a 1 in 3 chance of
being
a winner.  Eliminate one door and each door has a 1 in 2 chance of being
a
winner.  It matters not whether the third door is eliminated during the
game
or before the game starts.

And Arthur, while your door just increased from 1 in 3 to 1 in 2, so did
the
other door.  It matters not whether you switch or whether you stay, you
have
a 50/50 chance of winning.  There is no particular reason to switch, but
you
don't affect your odds in the slightest by switching.  Pick a door (of
the
two remaining), any door, and you have a 50/50 chance.

John W. Colby
www.ColbyConsulting.com 

Contribute your unused CPU cycles to a good cause:
http://folding.stanford.edu/

-----Original Message-----
From: dba-tech-bounces at databaseadvisors.com
[mailto:dba-tech-bounces at databaseadvisors.com] On Behalf Of Stuart
McLachlan
Sent: Thursday, August 25, 2005 10:20 PM
To: Discussion of Hardware and Software issues
Subject: Re: [dba-Tech] The Three Doors Problem


On 25 Aug 2005 at 20:04, Arthur Fuller wrote:

> I am the host of a TV program and you are the guest. This is the deal:

> there are 3 doors. Behind one of them is $100 million. Behind the
> other two are a dead catfish and a dead pickerel respectively. I 
> invite you to select a door. You choose any one of the three: call it 
> x I open another door, and say, Had you selected door y, you would 
> have won a dead catfish. Now, would you like to stick with your 
> original choice or switch to the other door? Does it matter? If not, 
> why not? If so, why so? There is a clear answer to this problem. Who 
> is going to be the first to come up with it? Arthur
> 
> 

Ah, the good old Monty Hall puzzle.

Strictly speaking, you need to qualify it by saying "I open another door

which I know contains a dead fish and show you the contents"  If you
could 
open the money door by accident, it is a different situation.

Anyhoo, the answers is:
Yes it matters, you should swap.  

I won't give the reason now  'cause it's a spoiler.   I know some peole 
will not agree with me and will go to great lengths to explain why I am 
wrong :-)






-- 
Stuart


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