A.D.Tejpal
adtp at touchtelindia.net
Thu Dec 18 12:03:08 CST 2003
Jim, Basically, there is nothing wrong with the use of variables as arguments to an Array() function. However, it has to be kept in mind that such arguments have to be interpretable as comma-delimited list of values. In the code originally sent by you, the whole string represented by variable StrStuff was getting interpreted as one vale (the commas treated as internal to the string). As a result you were getting a single element array and the value of varArray(0) was correctly being shown as the string containing all the three names. Sample code given below illustrates the use of variables as arguments to Array() function. Regards, A.D.Tejpal -------------- ------------- Code Start ------------- Sub TestArray() ' Return value of Array function is Variant type Dim varArray As Variant, StrStuff1 As String Dim StrStuff2 As String, StrStuff3 As String StrStuff1 = "Tom" StrStuff2 = "Dick" StrStuff3 = "Harry" ' Print strStuff1 To 3 Debug.Print StrStuff1 & ", " & StrStuff2 & ", " & StrStuff3 ' Output = Tom, Dick, Harry ' Run the ARRAY function to place the contents of ' strings into an array. (arguments for Array function ' have to be in the form of a comma-delimited list of values) varArray = Array(StrStuff1, StrStuff2, StrStuff3) ' Print the first index. Debug.Print varArray(0) ' Output = Tom End Sub ------------- Code End ------------- ----- Original Message ----- From: Jim Lawrence (AccessD) To: Access Developers discussion and problem solving Sent: Thursday, December 18, 2003 21:23 Subject: RE: [AccessD] The ARRAY function Jim Thanks for the information...much appreciated. The actual line feed in through variable was: "Tom", "Dick", "Harry" not "Tom, Dick, Harry" Visually there is no difference between the manually entered string and the 'generated' variable. I think the split function will work. Again THanks Jim -----Original Message----- From: accessd-bounces at databaseadvisors.com [mailto:accessd-bounces at databaseadvisors.com]On Behalf Of Jim DeMarco Sent: Thursday, December 18, 2003 5:16 AM To: Access Developers discussion and problem solving Subject: RE: [AccessD] The ARRAY function Yes that solved your problem but maybe some explanation on why your original code failed might help others? If not please read on. The difference between: strStuff = "Tom, Dick, Harry" varArray = Array(strStuff) Debug.Print varArray(0) 'prints "Tom, Dick, Harry" and varArray = Array ("Tom", "Dick", "Harry") Debug.Print varArray(0) 'prints "Tom" is that the Array function needs to be fed the individual array elements as separate arguments. Yes they look comma delimited but it's just to separate the arguments. Feeding in variable that contains strings separated by a comma is not the same thing. The Split function that worked for you took your string a created an array based on the "," delimiter which was then assigned to your variant. Jim DeMarco -----Original Message----- From: Jim Lawrence (AccessD) [mailto:accessd at shaw.ca] Sent: Wednesday, December 17, 2003 9:39 PM To: Access Developers discussion and problem solving Subject: RE: [AccessD] The ARRAY function Brilliant; Charlotte Many thanks. Jim -----Original Message----- From: accessd-bounces at databaseadvisors.com [mailto:accessd-bounces at databaseadvisors.com]On Behalf Of Charlotte Foust Sent: Wednesday, December 17, 2003 5:57 PM To: Access Developers discussion and problem solving Subject: RE: [AccessD] The ARRAY function If you want to use a variable, use Split instead of Array(). Then you don't need all those extra chr(34)s, etc. Public Function TestArray() Dim strStuff As String Dim vararray As Variant strStuff = "Tom, Dick, Harry" Debug.Print strStuff ' Run the Split function to place the contents of the string into an array. vararray = Split(strStuff, ",") Debug.Print vararray(0) End Function Charlotte Foust -----Original Message----- From: Jim Lawrence (AccessD) [mailto:accessd at shaw.ca] Sent: Wednesday, December 17, 2003 5:28 PM To: Access Developers discussion and problem solving Subject: [AccessD] The ARRAY function Hi All: I am running in some strange responses, maybe too much chocolate has fuddled the brain but: Given the following: ' Set strStuff strStuff = chr(34) & "Tom" & chr(34) & ", " & chr(34) & "Dick" & chr(34) & ", " & chr(34) & "Harry" & chr(34) ' Print strStuff ? strStuff "Tom", "Dick", "Harry" ' Run the ARRAY function to place the contents of the string into an array. varArray = Array(strStuff) ? varArray(0) ' Print the first index. "Tom", "Dick", "Harry" ' OK ????? ' Now type in the same information manually or cut and paste... varArray = Array("Tom", "Dick", "Harry") ? varArray(0) ' and the results are what they should be. Tom What is going on and why can a variable not be used in the ARRAY function?? :-( Any suggestions would be greatly appreciated. Jim