Jim Lawrence (AccessD)
accessd at shaw.ca
Thu Dec 18 19:56:50 CST 2003
Hi Jim:
It is not a right or wrong issue, it is an issue of how a program variable
is handled differently from the variable's contents, from one built in
function to another. I have learned something new.
Thanks
Jim
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com]On Behalf Of Jim DeMarco
Sent: Thursday, December 18, 2003 12:21 PM
To: Access Developers discussion and problem solving
Subject: RE: [AccessD] The ARRAY function
I think you misunderstood me. Yes you can pass variables to Array as
arguments as long as you separate your arguments with comma (as you've done
here). I was pointing out that the string "Tom, Dick, Harry" passed into
Array as one string is not the same thing as passing each individual item as
separate arguments to Array (whether literal or variable).
Jim DeMarco
-----Original Message-----
From: A.D.Tejpal [mailto:adtp at touchtelindia.net]
Sent: Thursday, December 18, 2003 1:03 PM
To: Access Developers discussion and problem solving
Subject: Re: [AccessD] The ARRAY function
Jim,
Basically, there is nothing wrong with the use of variables as arguments
to an Array() function. However, it has to be kept in mind that such
arguments have to be interpretable as comma-delimited list of values.
In the code originally sent by you, the whole string represented by
variable StrStuff was getting interpreted as one vale (the commas treated as
internal to the string). As a result you were getting a single element array
and the value of varArray(0) was correctly being shown as the string
containing all the three names.
Sample code given below illustrates the use of variables as arguments to
Array() function.
Regards,
A.D.Tejpal
--------------
-------------
Code Start
-------------
Sub TestArray()
' Return value of Array function is Variant type
Dim varArray As Variant, StrStuff1 As String
Dim StrStuff2 As String, StrStuff3 As String
StrStuff1 = "Tom"
StrStuff2 = "Dick"
StrStuff3 = "Harry"
' Print strStuff1 To 3
Debug.Print StrStuff1 & ", " & StrStuff2 & ", " & StrStuff3
' Output = Tom, Dick, Harry
' Run the ARRAY function to place the contents of
' strings into an array. (arguments for Array function
' have to be in the form of a comma-delimited list of values)
varArray = Array(StrStuff1, StrStuff2, StrStuff3)
' Print the first index.
Debug.Print varArray(0)
' Output = Tom
End Sub
-------------
Code End
-------------
----- Original Message -----
From: Jim Lawrence (AccessD)
To: Access Developers discussion and problem solving
Sent: Thursday, December 18, 2003 21:23
Subject: RE: [AccessD] The ARRAY function
Jim
Thanks for the information...much appreciated.
The actual line feed in through variable was:
"Tom", "Dick", "Harry" not "Tom, Dick, Harry"
Visually there is no difference between the manually entered string and
the
'generated' variable.
I think the split function will work.
Again THanks
Jim
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com]On Behalf Of Jim DeMarco
Sent: Thursday, December 18, 2003 5:16 AM
To: Access Developers discussion and problem solving
Subject: RE: [AccessD] The ARRAY function
Yes that solved your problem but maybe some explanation on why your
original
code failed might help others? If not please read on.
The difference between:
strStuff = "Tom, Dick, Harry"
varArray = Array(strStuff)
Debug.Print varArray(0) 'prints "Tom, Dick, Harry"
and
varArray = Array ("Tom", "Dick", "Harry")
Debug.Print varArray(0) 'prints "Tom"
is that the Array function needs to be fed the individual array elements
as
separate arguments. Yes they look comma delimited but it's just to
separate
the arguments. Feeding in variable that contains strings separated by a
comma is not the same thing.
The Split function that worked for you took your string a created an array
based on the "," delimiter which was then assigned to your variant.
Jim DeMarco
-----Original Message-----
From: Jim Lawrence (AccessD) [mailto:accessd at shaw.ca]
Sent: Wednesday, December 17, 2003 9:39 PM
To: Access Developers discussion and problem solving
Subject: RE: [AccessD] The ARRAY function
Brilliant; Charlotte
Many thanks.
Jim
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com]On Behalf Of Charlotte
Foust
Sent: Wednesday, December 17, 2003 5:57 PM
To: Access Developers discussion and problem solving
Subject: RE: [AccessD] The ARRAY function
If you want to use a variable, use Split instead of Array(). Then you
don't need all those extra chr(34)s, etc.
Public Function TestArray()
Dim strStuff As String
Dim vararray As Variant
strStuff = "Tom, Dick, Harry"
Debug.Print strStuff
' Run the Split function to place the contents of the string into an
array.
vararray = Split(strStuff, ",")
Debug.Print vararray(0)
End Function
Charlotte Foust
-----Original Message-----
From: Jim Lawrence (AccessD) [mailto:accessd at shaw.ca]
Sent: Wednesday, December 17, 2003 5:28 PM
To: Access Developers discussion and problem solving
Subject: [AccessD] The ARRAY function
Hi All:
I am running in some strange responses, maybe too much chocolate has
fuddled the brain but:
Given the following:
' Set strStuff
strStuff = chr(34) & "Tom" & chr(34) & ", " & chr(34) & "Dick" & chr(34)
& ", " & chr(34) & "Harry" & chr(34) ' Print strStuff ? strStuff "Tom",
"Dick", "Harry" ' Run the ARRAY function to place the contents of the
string into an array. varArray = Array(strStuff) ? varArray(0) ' Print
the first index. "Tom", "Dick", "Harry" ' OK ????? ' Now type in the
same information manually or cut and paste... varArray = Array("Tom",
"Dick", "Harry") ? varArray(0) ' and the results are what they should
be. Tom
What is going on and why can a variable not be used in the ARRAY
function?? :-(
Any suggestions would be greatly appreciated.
Jim
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