[AccessD] Re: Help, date diff

Oleg,

You need to rename your table.  DATE is a reserved word in Access and you 
are probably hitting that as an issue.

I would recommend naming it tsys_LastDate.  You know it is a table 
(t).  You know the system uses it (sys).  And, you know it's function (Last 
Date).

Also, I would name your command button something other than Command1.

Something like this would work:

Sub Check_Run_Date()
      dim db as database, rs as recordset
      set db = currentdb()
      set rs = db.openrecordset("SELECT * FROM tsys_LastDate;", dbopendynaset)
      if DateDiff("h", rs!LDate, now()) > 14 then
           rs.edit
                rs!LDate = now()
           rs.update
      Else
           msgbox ("The function was already performed today")
      End If
      rs.close
      set db = nothing
End Sub


At 11:45 AM 10/9/2003 -0500, you wrote:
>Date: Thu, 9 Oct 2003 10:07:20 -0400 (EDT)
>From: <Oleg_123 at xuppa.com>
>Subject: Re: [AccessD] Help, date diff
>To: <accessd at databaseadvisors.com>
>Message-ID: <48692.12.3.132.98.1065708440.squirrel at heck.bay9.com>
>Content-Type: text/plain; charset=iso-8859-1
>
>Thanks Stuart,
>this works goo, exsept I am still not able to update the table...
>With this line commented, it works
>DoCmd.RunSQL "Update Date Set ldate = Now()"
>
>Also, I'd like it to be performed on opening of the database. Is that
>possible ?
>
>
>Private Sub Command1_Click()
>
>last_time = DLookup("ldate", "Date")
>nnow = Now()
>
>andy = DateDiff("h", last_time, nnow)
>
>If andy > 14 Then
>    DoCmd.SetWarnings False
>   ' DoCmd.RunSQL "Update Date Set ldate = Now()"
>     msgbox ("ok")
>    DoCmd.SetWarnings True
>Else
>     msgbox ("The function was already performed today")
>End If
>
>End Sub