Jim DeMarco
Jdemarco at hshhp.org
Thu Oct 23 07:07:34 CDT 2003
Darren why not use a recordset filtering it by [OptionID = 1] to hold the values in your MyCriteria fields and set y = rs.Fields().Value? 'watch for wrapping <more pseudocode> Dim sSQL As String Dim rs As Recordset sSQL = "SELECT MyCriteria1, MyCriteria2, MyCriteria3, MyCriteria4, MyCriteria5, MyCriteria6 FROM tblOptions WHERE OptionID = 1" For x = 1 to 6 y = rs.Fields(x - 1).Value Me.Controls("MyControl" & x) = y Next x </more pseudocode> HTH, Jim DeMarco Director Product Development Hudson Health Plan -----Original Message----- From: Darren DICK [mailto:d.dick at uws.edu.au] Sent: Thursday, October 23, 2003 7:47 AM To: AccessD List Subject: [AccessD] A2K: DlookUp in a For Next Loop Hello all I have a table called tblOptions Int it are 6 fields each sequentially numbered MyCriteria1,MyCriteria2,MyCriteria3,MyCriteria4,MyCriteria5,MyCriteria6 I have a form with 6 controls on it called MyControl1, MyControl2,MyControl3 etc. The form they are on is not bound in any way to the table tblOptions. So what I wanted to do was a "for next" loop using DlookUp, but I can't get it right. :-( In psuedo code I want something like... Dim x, y For x = 1 To 6 y = DLookup("[MyCriteria & x]", "tblOptions", "[OptionID] = 1") Me.MyControl" & x = y Next Of course this doesn't work and I know I could do soemthing like Me.MyControl1 = DLookup("[MyCriteria1]", "tblOptions", "[OptionID] = 1") Me.MyControl2 = DLookup("[MyCriteria2]", "tblOptions", "[OptionID] = 1") Me.MyControl3 = DLookup("[MyCriteria3]", "tblOptions", "[OptionID] = 1") etc but I wanted something neater Many thanks in advance Darren _______________________________________________ AccessD mailing list AccessD at databaseadvisors.com http://databaseadvisors.com/mailman/listinfo/accessd Website: http://www.databaseadvisors.com *********************************************************************************** "This electronic message is intended to be for the use only of the named recipient, and may contain information from Hudson Health Plan (HHP) that is confidential or privileged. If you are not the intended recipient, you are hereby notified that any disclosure, copying, distribution or use of the contents of this message is strictly prohibited. If you have received this message in error or are not the named recipient, please notify us immediately, either by contacting the sender at the electronic mail address noted above or calling HHP at (914) 631-1611. If you are not the intended recipient, please do not forward this email to anyone, and delete and destroy all copies of this message. Thank You". ***********************************************************************************