John Skolits
askolits at ot.com
Fri Sep 12 05:41:14 CDT 2003
That would work also but if there is only one value in the SearchIn string,
it would not have a comma. Still, a thought I did not think of.
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com]On Behalf Of Erwin Craps
Sent: Friday, September 12, 2003 2:07 AM
To: Access Developers discussion and problem solving
Subject: RE: [AccessD] instr() - Need an exact match
Euh, you could also use this when you are sure the values are seperated
by a komma.
InStr(1,"a_Group,b_Group,c_Group" & "," , "c_Group" & "," ,c)
By adding the "," in bot strings you make the search string more unique.
You must be sure that no komma is used in the group names.
If you build the to be searched string yourself use chr(13) for as a
delimiter and replace the addedd "," by a chr(13).
vbBinaryCompare is only needed if you really wanna match.
This means a_group is NOT the same as a_Group
At my knowledge instr is much faster than strcomp.
So if you gonna have 10000 of iterations inst is faster.
Erwin
Erwin Craps
Zaakvoerder
www.ithelps.be/jonathan
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-----Oorspronkelijk bericht-----
Van: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] Namens John Skolits
Verzonden: vrijdag 12 september 2003 4:06
Aan: Access Developers discussion and problem solving
Onderwerp: RE: [AccessD] instr() - Need an exact match
Gee, I didn't expect you guys to spend all that time on this but it is
greatly appreciated.
Function works as ordered.
Thanks!!
John
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com]On Behalf Of Brett Barabash
Sent: Thursday, September 11, 2003 5:46 PM
To: 'Access Developers discussion and problem solving'
Subject: RE: [AccessD] instr() - Need an exact match
So what you really need to do is compare the portion between the
delimiters (commas). Here is a function that illustrates this:
Public Function ExactMatch(ByVal strSearchIn As String, ByVal
strSearchFor As String) As Boolean
Dim lngPos1 As Long
Dim lngPos2 As Long
lngPos1 = InStr(strSearchIn, strSearchFor)
If lngPos1 > 0 Then
lngPos2 = InStr(lngPos1 + 1, strSearchIn & ",", ",")
If StrComp(Mid$(strSearchIn, lngPos1, lngPos2 - lngPos1),
strSearchFor) = 0 Then
ExactMatch = True
End If
End If
End Function
-----Original Message-----
From: Heenan, Lambert [mailto:Lambert.Heenan at aig.com]
Sent: Thursday, September 11, 2003 4:34 PM
To: 'Access Developers discussion and problem solving'
Subject: RE: [AccessD] instr() - Need an exact match
The trouble with just using strcomp that way is that it will give you a
false match if the search string contains the sought string like this
Searchstring = "ABCDE", SoughtString = "BC".
Your code will return 0 as the sought string is contained in the search
string, but John wants to find the exact string "BC" with only spaces,
commas or nothing either side of it.
Lambert
> -----Original Message-----
> From: Brett Barabash [SMTP:BBarabash at tappeconstruction.com]
> Sent: Thursday, September 11, 2003 5:25 PM
> To: 'Access Developers discussion and problem solving'
> Subject: RE: [AccessD] instr() - Need an exact match
>
> Oops,
> That should read: StrComp(Mid([StringToSearch],InStr([StringToSearch],
> [SearchFor]),Len([SearchFor])),[SearchFor])
>
> But you get the idea...
>
>
> -----Original Message-----
> From: Brett Barabash [mailto:BBarabash at tappeconstruction.com]
> Sent: Thursday, September 11, 2003 3:57 PM
> To: 'Access Developers discussion and problem solving'
> Subject: RE: [AccessD] instr() - Need an exact match
>
>
> How about:
>
> StrComp(Mid(InStr([StringToSearch],
> [SearchFor]),Len([SearchFor])),[SearchFor])
>
>
> -----Original Message-----
> From: John Skolits [mailto:askolits at ot.com]
> Sent: Thursday, September 11, 2003 3:36 PM
> To: Access Developers discussion and problem solving
> Subject: RE: [AccessD] instr() - Need an exact match
>
>
> Here is a better example. In this case both function return a 1
>
>
> StrComp("SecGrp_Eng_Super, secGrp_Admin", "SecGrp_Eng_Super")
>
>
> StrComp("SecGrp_Eng_Super, secGrp_Admin", "SecGrp_Eng")
>
> The first one is an exact match, the second a partial match. I want to
> distinguish between the two.
>
>
>
>
>
> -----Original Message-----
> From: accessd-bounces at databaseadvisors.com
> [mailto:accessd-bounces at databaseadvisors.com]On Behalf Of Heenan,
> Lambert
> Sent: Thursday, September 11, 2003 4:13 PM
> To: 'Access Developers discussion and problem solving'
> Subject: RE: [AccessD] instr() - Need an exact match
>
>
> I'm not clear on why InStr() does not suit your purpose.
>
> InStr("a_Group,b_Group,c_Group","c_Group") will return a non-zero
> value (17), meaning that "c_Group" was found in the first string. Now
> if you want an exact match that takes the case into account you can
> use...
>
> InStr(1,"a_Group,b_Group,c_Group","c_group",vbBinaryCompare) ' note,
> must supply the start position - 1
>
> which will return zero as "c_group" is not found, whereas
>
> InStr(1,"a_Group,b_Group,c_Group","c_Group",vbBinaryCompare)
>
> returns 17.
>
> Lambert
>
> > -----Original Message-----
> > From: John Skolits [SMTP:askolits at ot.com]
> > Sent: Thursday, September 11, 2003 3:54 PM
> > To: Access Developers discussion and problem solving
> > Subject: [AccessD] instr() - Need an exact match
> >
> > Is there a way to do an exact match with something like Instr(). I
> > don't want a partial match.
> >
> > For example:
> > I have a string: "SecGrp_Admin, SecGrp_Eng, SecGro_User"
> >
> > I want to look see if "SecGrpAdmin_Super" is in the string. Instr()
> > will return a value but I want an exact match.
> >
> > I know I can parse the string and look for an exact match based on
> > the parsed value. I just thought maybe there's a function I can use
> > that
> would
> > do an Exact match test.
> >
> > John Skolits
> >
> >
> >
> >
> > _______________________________________________
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