John W. Colby
jwcolby at colbyconsulting.com
Thu Feb 12 20:31:29 CST 2004
This appears to work:
'
'Checks whether a time is "between" two other times
'
Function TimeIsBetween(dteTimeFrom As Date, dteTimeTo As Date,
dteTimeToCompare As Date) As Boolean
Select Case dteTimeFrom
Case Is < dteTimeTo
'Normal window, i.e. 6:00 pm to 11:00 pm
If (dteTimeToCompare >= dteTimeFrom) _
And (dteTimeToCompare <= dteTimeTo) Then
TimeIsBetween = True
End If
Case Is > dteTimeTo
'midnight crossing window, i.e. 6:00 pm to 1:00 am
If (dteTimeToCompare >= dteTimeFrom) _
Or (dteTimeToCompare <= dteTimeTo) Then
TimeIsBetween = True
End If
Case Else 'times are the same so now() must equal both
If (dteTimeToCompare = dteTimeFrom) _
And (dteTimeToCompare = dteTimeTo) Then
TimeIsBetween = True
End If
End Select
End Function
John W. Colby
www.ColbyConsulting.com
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com]On Behalf Of Stuart
McLachlan
Sent: Thursday, February 12, 2004 9:21 PM
To: Access Developers discussion and problem solving
Subject: Re: [AccessD] time window
On 12 Feb 2004 at 21:09, John W. Colby wrote:
> I need to be able to express a pure time window (not date related) from /
to
> and test time() as being between (inside) this time window. This process
> doesn't work across midnight, i.e. 7:00 pm is "between" 6:00 pm and 1:00
am.
> However if I just do a simple compare - 7:00 PM is >= 6:00 PM but it is
not
> <= 1:00 am.
>
> It looks like a "if time 2 > time 1 then use simple test for time()" "If
> Time 2 < time 1 then invert the second time comparison"
>
> Has anyone done this already?
>
Since times are actually stored as date/times with an integer part of
0, you can just use:
If time2 < time1 then time2 = time2 + 1
--
Lexacorp Ltd
http://www.lexacorp.com.pg
Information Technology Consultancy, Software Development,System
Support.
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