Gustav Brock
gustav at cactus.dk
Thu Jan 8 10:41:45 CST 2004
Hi Cynthia If you wish to use the features of formatting a date/time-value you need to convert the amount of minutes to a timevalue - like here where the amount of time is in hours: <code> Function TimeHour(ByVal curHMS As Currency) As Date ' Rounds and converts curHMS (number of hours as decimalnumber). ' Returns a time value, hh:nn:ss. ' Gustav Brock, Cactus Data ApS. ' 1999-08-12. Dim lngH As Long Dim lngM As Long Dim lngS As Long Dim curR As Currency ' No error handling needed. On Error Resume Next ' Round to two decimals, and skip number of days if curHMS > 24. ' If day count is needed, omit modulus like this: ' curHMS = (CLng(curHMS * 10000) / 100 * 36) ' Mod 86400 curHMS = (CLng(curHMS * 10000) / 100 * 36) Mod 86400 ' Calculate hours, minutes, and seconds. lngH = Int(curHMS / 3600) curR = curHMS - (lngH * 3600) lngM = Int(curR / 60) curR = curR - (lngM * 60) lngS = CInt(curR) ' Create time value. TimeHour = TimeSerial(lngH, lngM, lngS) End Function </code> Or you could try to simply feed your amount of minutes directly: datTime = TimeSerial(0, lngMinutes, 0) That may work - haven't tested it though. /gustav > I have an application that tracks the amount of time spent on projects. I used DateDiff on the entry form in order to get the number of minutes between the start and end times. The number is held > in a field called "Time." In a report, I sum "Time" in order to get the total number of minutes. I need to show the total minutes in hh:mm format on the report. I tried to simply format the > field in the report, but that didn't work. > I tried dividing the minutes by 60, which gave me the number of hours and a remainder. I then multiplied the remainder by 60 and then divided by 100 to get the number of seconds. This is getting > ugly.... Am I making this harder than it is??