Gustav Brock
gustav at cactus.dk
Tue Sep 14 07:51:44 CDT 2004
Hi Darren
That could be:
lngDiff = DateDiff("n", [LogonTimeAndDate], Now())
To get hours and minutes:
lngH = lngDiff \ 60
lngM = lngDiff Mod 60
To convert to a pseudo time value for easy formatting:
datTime = TimeSerial(lngH, lngM, 0)
strTime = Format(datTime, "h:nn")
Be careful, though, if users (their machines) happen to be logged in
for more than 24 hours.
/gustav
> I want to calculate then insert into a table the duration of a users logon
> in HOURS and MINUTES
> In the logon table the default value for the logon field is Now() and is
> captured at...You guessed at logon. I then run a query that updates the
> Logoff field to Now() once the user answers YES to loggin off. The theory
> being there will be a difference even if it is only 5 or 10 seconds. Unless
> some clown plays with the clock after loggin on --- but forget all that :-))
> Both logon and logoff fields data types in the Logon Table are General Date
> (01/01/2004 15:45:25PM)
> So a user logs on at say...14/09/2004 10:08:45 PM and then logs off at
> say...14/09/2004 10:10:55 PM
> The time logged on = 2 mins and 10 secs but how do I calculate that?
> I have udsed DateDiff but with no success...
> DateDiff("Short Time",[LogonTimeAndDate],Now())
> DateDiff("mm",[LogonTimeAndDate],Now())
> DateDiff("nn",[LogonTimeAndDate],Now()) etc etc
> Many thanks in advance
> Darren