Gustav Brock
Gustav at cactus.dk
Thu Aug 25 05:57:04 CDT 2005
Hi Jim Here's the real simple method: SELECT Len([fldText])-Len(Replace([fldText], '|', '')) AS Occurrences FROM ... If you expect Null values use: Len([fldText])-Len(Replace('' & [fldText], '|', '')) AS Occurrences to prevent errors. If you want a count of zero even for Null values: Len('' & [fldText])-Len(Replace('' & [fldText], '|', '')) AS Occurrences For Access 97 and below you'll need to supply the Replace() function too. /gustav >>> Jim.Hale at FleetPride.com 24-08-2005 17:51 >>> Assume I have a text field in a table. Further assume that the text strings are delimited by the pipe character "|". I want to know how many pipe characters occur in each field, ie. the select statement should return: fldText Occurrences test|ddd|ww|ex 3 fff|sss 1 eenie|meenie|minie|moe 3 What is the correct SQL to produce the desired result? TIA Jim Hale