Gustav Brock
Gustav at cactus.dk
Wed Jan 12 14:05:41 CST 2005
Hi Pedro Bob is right but you need to Group By on the fields too: SELECT Avg(tblGroup1.FieldA+tblGroup2.FieldB)/2 AS Avg2 FROM tblGroup1, tblGroup2 GROUP BY tblGroup1.FieldA, tblGroup2.FieldB; /gustav >>> pedro at plex.nl 12-01-2005 20:29:14 >>> Hello Rob, i know its a Cartesian query. I used one in the past (from Gustav Brock), but that was a total different query and situation. In the help i couldn't find an example of a normal Cartesian query. Your query only gives me one result. I need every single average of the 4 calculations. let me explain a little bit better. i have tblGroup1 FieldA 2 3 tblGroup2 FieldB 4 5 I need QueryAverage "avg(2+4 /2) =" 3 "avg(3+4 /2) =" 3,5 "avg(2+5 /2) =" 3,5 "avg(3+5 /2) =" 4 I'll hope this explaines a little more. - Pedro - ----- Original Message ----- From: "Bob Hall" <rjhjr at cox.net> To: <AccessD at databaseadvisors.com> Sent: Wednesday, January 12, 2005 4:39 PM Subject: Re: [AccessD] complex query!! > On Wed, Jan 12, 2005 at 01:51:38PM +0100, Pedro Janssen wrote: > > Hello group, > > > > for a statistic analyses of DNA-samples i need to compare each sample from a group with eachother sample from another group. I have 7 groups with up to 17 samples. Let me explain what i need in an example. > > > > I have > > > > Two tables group1 and group2, with each two records. > > > > > > i need the average of: > > group1_record1 + group2_record1 > > group1_record2 + group2_record1 > > group1_record1 + group2_record2 > > group1_record2 + group2_record2 > > > > > > and this for 7 groups up to 17 records > > > > > > Is this possible in a query per 2 groups, > > or can this been done in total by code? > > Pedro, your example is a little ambiguous. Assuming that you want to add > records and take the average, and not add columns and take the average, > the query is a simple Cartesian product. Assuming a column in group1 > named First and a column in group2 named Second: > > SELECT Avg(group1.First + group2.Second) AS Mean > >From group1, group2; > > If you had tables with thousands of records, this would take forever to > run. But as long as you've got less than 100 records in each table, it > should be OK. > > I apologize if I misunderstand what you're trying to do. > > Bob Hall