Steve Erbach
erbachs at gmail.com
Fri Jan 21 15:33:29 CST 2005
Scott, Oooh! Good one. I think that'll do it, as long as the Keys are nice and sequential. Steve Erbach On Fri, 21 Jan 2005 15:39:42 -0500, Scott Marcus <marcus at tsstech.com> wrote: > The answer is the following, where id is the primary key of Table1... > > SELECT ([a].[factor]+[b].[factor])/2 AS Average_OF_Factor, > a.factor, > b.factor > FROM Table1 AS a, > Table1 AS b > WHERE [a].[id]<[b].[id]; > > Scott Marcus > TSS Technologies, Inc. > marcus at tsstech.com > (513) 772-7000 >