Gustav Brock
Gustav at cactus.dk
Fri Sep 23 09:29:51 CDT 2005
Hi Shamil Well, you _have_ a clue. You may wish to read my hint again ... A puzzle for me? Thanks! Will get to that later. /gustav >>> shamil at users.mns.ru 23-09-2005 15:27:25 >>> Gustav, One may guess the basis of notation isn't decimal and try the most obvious 5, 7 and 16 as a notation basis and convert the sequence to the numbers with decimal notation basis - then they will get: 10 11 12 13 14 20 22 31 5: 5 6 7 8 9 10 12 16 7: 7 8 9 10 11 14 16 22 16: 16 17 18 19 20 32 34 49 No clue :( Stupid idea: total quantity of any used digit should be even or odd and the answer should be greater than the last number in the sequence and the answer should have two digits?: Given: ===== 0 -> 2 1 -> 7 2 -> 4 3 -> 2 4 -> 1 With one additional number with two digits the quantity of every used digit can be made even. It can't be made odd. Target: ===== 0 -> 2 1 -> 8 2 -> 4 3 -> 2 4 -> 2 Answer: 41? It doesn't look like this answer deserve a a tasty chocolate but anyway for others to look for the right answer in other areas.... Shamil P.S. My Friday puzzle to you Gustav :) What is the missing number: 10 11 12 13 14 20 22 (?) 31 ----- Original Message ----- From: "Gustav Brock" <Gustav at cactus.dk> To: <accessd at databaseadvisors.com> Sent: Friday, September 23, 2005 3:06 PM Subject: Re: [AccessD] OT: Friday entertainment > Hi all > > We still have this open: > > 3. What is the next number in this series: > 10 11 12 13 14 20 22 31 ? > > It's quite clever in fact. A true nerd thing suited for any programmer. > A hint: The requested item is the last one possible ...(?!!) > > /gustav