Scott Marcus
marcus at tsstech.com
Fri Sep 23 13:24:28 CDT 2005
A Hitchhiker told me the answer is '42'. Scott Marcus IT Programmer TSS Technologies Inc. www.tss.com -----Original Message----- From: accessd-bounces at databaseadvisors.com [mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Shamil Salakhetdinov Sent: Friday, September 23, 2005 11:30 AM To: Access Developers discussion and problem solving Subject: Re: [AccessD] OT: Friday entertainment > Well, you _have_ a clue. OK, I have it but I don't see it. > You may wish to read my hint again ... Yes, I did read it: "A hint: The requested item is the last one possible" - still no wise sparks in my braincells.... Maybe the answer is 44? - the last one possible two digits number if we assume that 5 is a notation basis of the original sequence: 10 11 12 13 14 20 22 31 44 Even if the answer is correct - no clue why it's so.... Are the original numbers scancodes/codes for the core letters of keypad: ASDFGHJKL? These are nine letters and nine numbers are in the requested sequence - then hint works but still no clue how keypad letters correspond to the given numbers' sequence.... Maybe tomorrow I will give it another try if somebody else will not solve it before. No time on entertainment today, have to do some boring work... Thanks, Shamil ----- Original Message ----- From: "Gustav Brock" <Gustav at cactus.dk> To: <accessd at databaseadvisors.com> Sent: Friday, September 23, 2005 6:29 PM Subject: Re: [AccessD] OT: Friday entertainment > Hi Shamil > > Well, you _have_ a clue. > You may wish to read my hint again ... > > A puzzle for me? Thanks! Will get to that later. > > /gustav > > >>> shamil at users.mns.ru 23-09-2005 15:27:25 >>> > Gustav, > > One may guess the basis of notation isn't decimal and try the most obvious > 5, 7 and 16 as a notation basis and convert the sequence to the numbers > with decimal notation basis - then they will get: > > 10 11 12 13 14 20 22 31 > > 5: 5 6 7 8 9 10 12 16 > 7: 7 8 9 10 11 14 16 22 > 16: 16 17 18 19 20 32 34 49 > > No clue :( > > Stupid idea: total quantity of any used digit should be even or odd > and the answer should be greater than the last number in the sequence and > the answer should have two digits?: > > Given: > ===== > 0 -> 2 > 1 -> 7 > 2 -> 4 > 3 -> 2 > 4 -> 1 > > With one additional number with two digits the quantity of every used digit > can be made even. It can't be made odd. > > Target: > ===== > 0 -> 2 > 1 -> 8 > 2 -> 4 > 3 -> 2 > 4 -> 2 > > Answer: 41? > > It doesn't look like this answer deserve a a tasty chocolate but anyway for > others to look for the right answer in other areas.... > > Shamil > > P.S. My Friday puzzle to you Gustav :) > > What is the missing number: > > 10 11 12 13 14 20 22 (?) 31 > > > ----- Original Message ----- > From: "Gustav Brock" <Gustav at cactus.dk> > To: <accessd at databaseadvisors.com> > Sent: Friday, September 23, 2005 3:06 PM > Subject: Re: [AccessD] OT: Friday entertainment > > > > Hi all > > > > We still have this open: > > > > 3. What is the next number in this series: > > 10 11 12 13 14 20 22 31 ? > > > > It's quite clever in fact. A true nerd thing suited for any programmer. > > A hint: The requested item is the last one possible ...(?!!) > > > > /gustav > > > -- > AccessD mailing list > AccessD at databaseadvisors.com > http://databaseadvisors.com/mailman/listinfo/accessd > Website: http://www.databaseadvisors.com -- AccessD mailing list AccessD at databaseadvisors.com http://databaseadvisors.com/mailman/listinfo/accessd Website: http://www.databaseadvisors.com