Hale, Jim
Jim.Hale at FleetPride.com
Thu Feb 2 11:31:00 CST 2006
y = appXcel.WorksheetFunction.CountA(wksUpl.Range("A:A")) counts the of cells that are not empty in the specified range. This works great assuming the indicated column does not have empty cells interspersed. Btw way why not use dynamic ranges? Ie the range names in Excel automatically change depending on their size. See http://www.ozgrid.com/Excel/DynamicRanges.htm Jim Hale -----Original Message----- From: John Colby [mailto:jwcolby at colbyconsulting.com] Sent: Thursday, February 02, 2006 11:01 AM To: 'Access Developers discussion and problem solving' Subject: [AccessD] How many rows populated in range Does anyone know how to determine how many rows of a range are actually populated with data? I have a range with Doc DocDescr Otherstuff etc 1A Some Desce Etc Etc 1Ai Other Descr Etc Etc The range is potentially up to a hundred and some rows. Doc and DocDescr will always have data in it, but the other columns might not. Is there any property of the range that says what the last occupied row is? Are there iterators for ranges, i.e. "for each row in Range" kind of thing? John W. Colby www.ColbyConsulting.com -- AccessD mailing list AccessD at databaseadvisors.com http://databaseadvisors.com/mailman/listinfo/accessd Website: http://www.databaseadvisors.com *********************************************************************** The information transmitted is intended solely for the individual or entity to which it is addressed and may contain confidential and/or privileged material. Any review, retransmission, dissemination or other use of or taking action in reliance upon this information by persons or entities other than the intended recipient is prohibited. If you have received this email in error please contact the sender and delete the material from any computer. As a recipient of this email, you are responsible for screening its contents and the contents of any attachments for the presence of viruses. No liability is accepted for any damages caused by any virus transmitted by this email.