Stuart McLachlan
stuart at lexacorp.com.pg
Sun Jan 8 23:09:36 CST 2006
On 8 Jan 2006 at 20:39, Joe Hecht wrote: > > datenow = Now() > dateborn = Me.DOB > Me.txtage = DateDiff("yyyy", datenow, dateborn) > This will not always give the correct age since it only works on the year part and doesn't take into account the actual dates. It will be one year too high if datenow is earlier in the year than dateborn. ie DateDiff("yyyy","31 Dec 05","1 Jan 06") will return 1 even though it is only one day difference (to say nothing of your version always returning a negative value because the arguments are the wrong way round) Try Me.txtage = Datediff("yyyy",dateborn,datenow) + _ (DatePart("y", datenow) < DatePart("y",dateborn)) -- Stuart