Bobby Heid
bheid at appdevgrp.com
Tue Jan 17 06:52:05 CST 2006
Hi Arthur, This is what we use in Access XP: Public Function GetFilePath(lstrFileName) As String 'Returns the directory of the passed file name. 'Expects the full path and file name as input. GetFilePath = Left(lstrFileName, InStrRev(lstrFileName, "\")) End Function Bobby -----Original Message----- From: accessd-bounces at databaseadvisors.com [mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Arthur Fuller Sent: Saturday, January 14, 2006 7:16 AM To: 'Access Developers discussion and problem solving' Subject: Re: [AccessD] Compact by code Where is the code for GetFilePath()? I have something vaguely similar but I figured rather than experiment with making mine and yours compatible, I would simply ask for it. Arthur -----Original Message----- From: accessd-bounces at databaseadvisors.com [mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Bobby Heid Sent: Monday, November 21, 2005 12:54 PM To: 'Access Developers discussion and problem solving' Subject: Re: [AccessD] Compact by code Sorry, GetFilePath() returns the path of a given file name string. Bobby -- AccessD mailing list AccessD at databaseadvisors.com http://databaseadvisors.com/mailman/listinfo/accessd Website: http://www.databaseadvisors.com