[AccessD] bust out the math books

Sorry Real Average should be...

(ADFHJ+CBFHJ+EBDHJ+GBDFJ+IBDFH)/BDFHJ

Still, the two do not equal.

-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Scott Marcus
Sent: Wednesday, January 25, 2006 7:51 AM
To: Access Developers discussion and problem solving
Subject: Re: [AccessD] bust out the math books

Mathematical answer...

C1 = Total
C2 = Sample Size
C3 = Average

C1  C2  C3
===========
A   B   A/B
C   D   C/D
E   F   E/F
G   H   G/H
I   J   I/J


Real average = (A+C+E+G+I)/BDFHJ

Average of averages = (A/B + C/D + E/F + G/H + I/J)/5

Which equals...
((ADFHJ+CBFHJ+EBDHJ+GBDFJ+IBDFH)/(BDFHJ))/5
                    

Which equals...
(ADFHJ+CBFHJ+EBDHJ+GBDFJ+IBDFH)/5BDFHJ


(A+C+E+G+I)/BDFHJ does not equal 
(ADFHJ+CBFHJ+EBDHJ+GBDFJ+IBDFH)/5BDFHJ


Scott Marcus                   

-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Francisco
Tapia
Sent: Tuesday, January 24, 2006 7:50 PM
To: Access Developers discussion and problem solving
Subject: [AccessD] bust out the math books

can someone answer me this:
  C1 C2
C3  1566 1770
0.884746  5130 5340
0.960674  1320 1800
0.733333  6440 7280
0.884615  1770 1800
0.983333



 16226 17990
0.901946
If I take C1 / C2 I get C3... there must be a mathimaticall reason as to
why
I can't just average column C3 to get the 90%, instead I end up with
88.93%

any thoughts?

--
-Francisco
http://pcthis.blogspot.com |PC news with out the jargon!
http://sqlthis.blogspot.com | Tsql and More...
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