[AccessD] Math in VBA

Thanks Everyone,

I ended up using a loop to get my powers...before I was the power by 1 for 
each record...now I added a new loop to get the actual number if you 
calculated out to the nth power.  I was in the quadrillions when I finished. 
  Thanks Again,

Mark

    Power = Power - 1
    PowerNum = CDec(36)
    For PNLoop = 1 To Power - 1
    PowerNum = CDec(PowerNum * CDec(36))
    Next


>From: "Gustav Brock" <Gustav at cactus.dk>
>Reply-To: Access Developers discussion and problem 
>solving<accessd at databaseadvisors.com>
>To: <accessd at databaseadvisors.com>
>Subject: Re: [AccessD] Math in VBA
>Date: Thu, 19 Jul 2007 21:25:42 +0200
>
>Hi Mark
>
>Chris is right. You have to keep the _numeric_ expressions within that of a 
>Long if you wish to maintain accuracy.
>
>Thus:
>? CDec(36 ^10)
>  3656158440062980
>? CDec(36 ^ 5) * CDec(36 ^ 5)
>  3656158440062976
>
>because CDec(36 ^ 5) = 60466176.
>
>/gustav
>
> >>> cjeris at fas.harvard.edu 19-07-2007 20:37 >>>
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>Mark A Matte wrote:
> > ttt = CDec(36 * 36 * 36)
>
>6^6 = 46656 overflows a 16-bit signed integer.  Now we can all line up
>and kick someone in the head for leaving a 16-bit signed integer type in
>a program written after 1995.
>
>Try
>ttt = CDec(36) * CDec(36) * CDec(36)
>
>Also, be careful!
> > tt = CDec(36 ^ 10)
>
>That ^ is the _floating_point_ exponentiation operator!  The result is
>not the integer 6^20; if you look at tt, you will see that it ends in a
>0, which no power of 6 does.  What you get there is the decimal
>conversion of the floating-point exponentiation.
>
>peace, Chris Jeris
>
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