[AccessD] Positioning a form with MoveSize command

Hi all,

I have a set of forms that I want to have always open at a certain 
position.  I've put this code into the On Activate event for each form:
- - -
DoCmd.MoveSize 6000, 1200
- - -

This set of forms simulates the Access Switchboard.  The Main Menu form 
has buttons for opening the Member Information Menu form and the 
Contribution Information Menu, etc.  The Member Information Menu form 
has a set of buttons, one of which recalls the Main Menu form (and 
closes the Member Information Menu form).  If I use the Main Menu button 
on the Member Information Menu, the Main Menu opens and is correctly 
positioned at 6000 twps from the left and 1200 twps from the top.  And 
navigating among the three menu forms is working fine - each form, when 
opened by the On Click event of the appropriate button, opens at the 
correct location.

However, if I open any one of these forms by double-clicking its icon in 
the Forms container, the form is located a little bit higher than the 
1200 twps - I don't know the exact number, but it is clearly higher than 
it should be.  If I start with the Main Menu form and click the button 
to open the Member Information Menu, that form opens in the correct 
position, slightly lower than the Main Menu.  If I then click the Main 
Menu button on the Member Information Menu, the Main Menu moves to the 
correct position and the Member Information Menu closes.

I've tried the DoCmd.MoveSize 6000, 1200 in the On Open, On Load, On 
Resize, On Current, and On Activate events, and I've been unable to get 
the forms (any one of them - they all do this thing) to open at the 
correct position when launched via double-click on their icon in the 
forms container.

What am I doing wrong?

Thanks for any guidance,
Tina