[AccessD] Form positioning another try

Hi Tina

I don't know, it is years ago I dealt with this - to have forms positioned at 0,0 when opened. If a toolbar was not present the form would move to the top menu and then the toolbar of the form would be covering the top of the form. And vice versa.

You could play with the timer of the form. Let 0.1 s pass after loading, then reposition the form and reset the timer?

/gustav

>>> tinanfields at torchlake.com 28-07-2008 17:27 >>>
Hi Gustav,

You are right, users won't be double-clicking in the Forms container.  
But, when I make frmMyForm the startup form, it locates in the same 
place as when double-clicked from the Forms container.  So, I am trying 
to understand what I must do to put this form in the position I want no 
matter how it is opened.  Perhaps by putting first a splash form and 
calling my frmMyForm from that?

Thanks for the thought about the presence of a top toolbar.  Shouldn't I 
be able then to open and load the form (maybe with Application.Echo 
False so the screen doesn't jump around), then have the On Current or On 
GotFocus event relocate the form to the proper place?  I haven't tried 
exactly that, so I will.

Any other thoughts?  Thank you,
Tina

Gustav Brock wrote:
> Hi Tina
>
> That could be because thinks when opening it by double-clicking, that a top toolbar is not present which - when the form loads - it is.
>
> But what does it matter? Users don't double-click in the Forms container ...
>
> /gustav
>
>   
>>>> tinanfields at torchlake.com 27-07-2008 20:43 >>>
>>>>         
> Hi,
>
> Didn't get anyone to bite on my previous query about this, so I'll try 
> it a little different way.
>
> I have a form we'll call frmMyForm.  I want it to be in a certain 
> position 6000 twps from the left edge of the window and 1200 twps from 
> the top edge of the window.
>
> If I put the DoCmd.MoveSize 6000, 1200 in the On Activate event of the 
> form and call the form from some other form with a command button that 
> has in its On Click event the DoCmd.OpenForm frmMyForm, all is well.  
> The frmMyForm opens in the desired position.  However, if I double-click 
> the icon for frmMyForm in the Forms container, frmMyForm opens in a 
> slightly higher position - about 400 twps higher, as a matter of fact.  Why?
>
> I've tried my DoCmd.MoveSize in every event I can think of that should 
> launch frmMyForm in the correct position - On Open, On Load, On Resize, 
> On Current, On Activate, On GotFocus - no go.  It works fine if called 
> by code attached to some command button, but it does not work when the 
> frmMyForm icon is double-clicked from the Forms container in the 
> Database window.  Why?
>
> What am I doing wrong here?  Thanks for any assistance.
>
> Tina