[AccessD] Find characters in one string that areinanother:w asRE: Treat string as array

You might not want this then,  but it is an alternative.

Max

Function tryRegEx()
  Dim lngResult As Long, strPwd As String
  strPwd = "~12+#xyz"
  lngResult = (RegExpTest("\W", strPwd))  ' uppercase W (   Matches any
nonword character)
  If lngResult > 0 Then MsgBox "Test 1: " & lngResult & " matched - as
non-alph"
  lngResult = (RegExpTest("\w", strPwd))   ' lowecase w ( Matches any word
character))
  If lngResult > 0 Then MsgBox "Test 2: " & lngResult & " matched as alpha"
  lngResult = (RegExpTest("\d", strPwd))    ' lowercase d (  Matches any
decimal digit.)
  If lngResult > 0 Then MsgBox "Test 3: " & lngResult & " matched - as
decimal"
End Function

Function RegExpTest(patrn, strng) As Long
' Set reference to Microsoft vbscript regular expressions 5.5
' Cheat Sheet available at http://regexlib.com/CheatSheet.aspx
  Dim RegEx As New VBScript_RegExp_55.RegExp
  Dim Match, Matches, RetStr  ' Create variable.
  Set RegEx = New RegExp   ' Create a regular expression.
  RegEx.Pattern = patrn   ' Set pattern.
  RegEx.IgnoreCase = True   ' Set case insensitivity.
  RegEx.Global = True   ' Set global applicability.
  Set Matches = RegEx.Execute(strng)   ' Execute search.
  RegExpTest = 0
  For Each Match In Matches   ' Iterate Matches collection.
    RetStr = RetStr & "Match found at position "
    RetStr = RetStr & Match.FirstIndex & ". Match Value is '"
    RetStr = RetStr & Match.Value & "'." & vbCrLf
    RegExpTest = RegExpTest + 1
  Next
End Function
  

-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of jwcolby
Sent: Tuesday, March 25, 2008 3:55 PM
To: 'Access Developers discussion and problem solving'
Subject: Re: [AccessD] Find characters in one string that areinanother:w
asRE: Treat string as array

Just an update, I have integrated Gustav's solution in my LWS and now have
password rule checking in place.

John W. Colby
Colby Consulting
www.ColbyConsulting.com
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Heenan, Lambert
Sent: Tuesday, March 25, 2008 11:15 AM
To: 'Access Developers discussion and problem solving'
Subject: Re: [AccessD] Find characters in one string that are inanother:w
asRE: Treat string as array

But John, didn't you see Gustav's response very early on in the thread
suggesting you use StrConv? Armed with that clue your dream of using a
simple for next loop is easily achieved...

Function StringArray(str As String) As Variant Dim byArray() As Byte
    byArray = StrConv(str, vbFromUnicode)
    StringArray = byArray
End Function

Sub PlayWithStringArray(str As String)
Dim byArray() As Byte
Dim c As Variant
    byArray = StringArray(str)
    For Each c In byArray()
        Debug.Print c; " "; Chr(c);
    Next c
    Debug.Print vbCrLf; str
End Sub

You're on the money though about the number of answers that seemed not to be
connected with the question! :-)

Lambert

-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of jwcolby
Sent: Tuesday, March 25, 2008 11:01 AM
To: 'Access Developers discussion and problem solving'
Subject: Re: [AccessD] Find characters in one string that are in
another:wasRE: Treat string as array


LOL.  

Turn a string into an array.  Turn a string into an ARRAY.  TURN A STRING
INTO AN ARRAY.  

That was my question.  Why I want to do it is irrelevant.

And yea, Regex probably would work, but I did not have time to spend a week
learning a useful but EXTREMELY arcane syntax to solve a 5 minute problem.
In fact I didn't have time to answer 25 suggestions having nothing to do
with TURNING A STRING INTO AN ARRAY. 

Sigh.

;-)

John W. Colby
Colby Consulting
www.ColbyConsulting.com

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