[AccessD] Figuring the date

I got this to work in SQL server, maybe someone can do something similar in
Access to help you out. Another thing would be to make a function.

SET DATEFIRST 1
DECLARE @Yr AS INT, @WkNo AS INT SELECT @Yr = 2009, @WkNo = 10
--SELECT DATEADD(week, @WkNo, ('1/1/' + CAST(@Yr AS VARCHAR(4)))) --Gives us
the date 10 weeks after jan 1st
SELECT DATEADD(DAY,1-DATEPART(dw,DATEADD(week, 10, ('1/1/' + CAST(@Yr AS
VARCHAR(4))))),DATEADD(week, @WkNo, ('1/1/' + CAST(@Yr AS VARCHAR(4)))))




On Fri, Mar 6, 2009 at 12:50 PM, Gary Kjos <garykjos at gmail.com> wrote:

> If it's for a finite group of years I would use a date table. It's the
> data warehouse way for things like that and I work in the data
> warehouse group, hence my leaning towards that. You pre-load the date
> table and your good. Until the pre-loaded dates pass by of course.
>
> GK
>
> On Fri, Mar 6, 2009 at 2:38 PM, Jennifer Gross <jengross at gte.net> wrote:
> > Okay, I have answers to my questions - they define Week 1 as the first
> > full week of the year and the week is defined as Monday to Sunday.  Any
> > thoughts on how to get that Monday date when I know the year and the
> > week #?
> >
> > Jennifer
> >
> > -----Original Message-----
> > From: accessd-bounces at databaseadvisors.com
> > [mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Jennifer
> > Gross
> > Sent: Friday, March 06, 2009 12:34 PM
> > To: AccessD List
> > Subject: [AccessD] Figuring the date
> >
> >
> > Hey Everyone,
> >
> > I have two pieces of information - the year and the week # within the
> > year, for instance 2008 13 is the 13th week in 2008.  I have questions
> > out to the client about how they define the week (Sun-Sat, Mon-Sun) and
> > how the first week of the year is defined - week that January 1 falls in
> > or first full week of the year.  Anyway - what I need to do is create a
> > function, unless one already exists, when fed these two pieces of
> > information returns the Monday date (short date format) for that week.
> >
> > Any help is appreciated.
> >
> > Jennifer
> >
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> Gary Kjos
> garykjos at gmail.com
>
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