Heenan, Lambert
Lambert.Heenan at chartisinsurance.com
Tue Nov 10 13:50:14 CST 2009
SELECT CDbl("123.45") AS SomeDouble, BankNames_tbl.BankID, CDbl([BankID]) AS dbl_BankID
FROM BankNames_tbl;
Gives
SomeDouble BankID dbl_BankID
123.45 1 1
123.45 2 2
Where BankID is an autonumber.
There's something wrong with JCs installation IMHO.
Lambert
-----Original Message-----
From: accessd-bounces at databaseadvisors.com [mailto:accessd-bounces at databaseadvisors.com] On Behalf Of David McAfee
Sent: Tuesday, November 10, 2009 2:36 PM
To: Access Developers discussion and problem solving
Subject: Re: [AccessD] Bug in access
Oops, you are correct. It still works for me
SELECT CDbl("123.45") AS Expr1, tblMyTable.CPName, CDbl([CPName]) AS Expr2 FROM tblMyTable;
Expr1 CPName Expr2
123.45 David McAfee #Error
123.45 Bill Gates #Error
123.45 Larry Ellison #Error
123.45 Megan Fox #Error
123.45 123.45 123.45
123.45 678.90 678.9
On Tue, Nov 10, 2009 at 11:06 AM, Charlotte Foust <cfoust at infostatsystems.com> wrote:
> Did I miss something or did you guys? I understood that John was specifically trying to use CDbl against a field name, not an explicit string. Is that correct, JC?
>
> Charlotte Foust