[AccessD] OT: Friday Puzzles

BTW, the answer for the fist puzzle is as straightforward as this code (C#):

public static int GetSurvivorNumber(int lineSize)
{
    return (int)Math.Pow(2, (int)Math.Log(lineSize / 2, 2) + 1);  
}

Got it last night "out of nowhere"... Of course Drew's original "brute
force" solution was a 'must have' step to get to the above 'lightweight'
answer... Or one have to get studied in the modern computer science colleges
where they are taught to "crack" such puzzles in seconds... 

Thank you.

-- Shamil

-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Max Wanadoo
Sent: Sunday, April 25, 2010 9:33 PM
To: 'Access Developers discussion and problem solving'
Subject: Re: [AccessD] OT: Friday Puzzles

Me too and the only one with the correct answer!!

Max
 

-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Drew Wutka
Sent: Sunday, April 25, 2010 5:33 PM
To: Access Developers discussion and problem solving
Subject: Re: [AccessD] OT: Friday Puzzles

Hey, I answered it!

Drew

-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Arthur Fuller
Sent: Saturday, April 24, 2010 8:27 AM
To: Access Developers discussion and problem solving
Subject: Re: [AccessD] OT: Friday Puzzles

As many of you figured out, position 512 is the surviving position.

It's very interesting how many of you readers are so easily diverted
from
what might have been productive work! I shall endeavour to come up with
more
puzzles for you all.

It's also interesting that you all focused on the survivor problem.
Everyone
seems to have ignored the other one.

Arthur
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