[AccessD] CurrentProject.Path syntax?

...I just concatenated the "\" and it works
...AccessD saved my bacon again :)

William

--------------------------------------------------
From: "Jim Lawrence" <accessd at shaw.ca>
Sent: Wednesday, March 17, 2010 4:01 PM
To: "'Access Developers discussion and problem solving'" 
<accessd at databaseadvisors.com>
Subject: Re: [AccessD] CurrentProject.Path syntax?

> Hi William:
>
> So what does CurrentPath resolve to?... "v:\JISWORKING\TMS\"
> You may have to pass the syntax through a variable like:
>
> strCurrentPath =  trim(CurrentProject.Path & "MBCC_HallC_Spring_001a.mdp")
> MetaDraw0.LoadPicture strCurrentPath
>
> This usually solves the problem. Also noted is you have curved brackets
> around the name in the first version which may indicate a return value 
> from
> the MetaDraw0 class which may confuse the simple thing...?
>
> HTH
> Jim
>
>
>
> -----Original Message-----
> From: accessd-bounces at databaseadvisors.com
> [mailto:accessd-bounces at databaseadvisors.com] On Behalf Of William Hindman
> Sent: Wednesday, March 17, 2010 8:31 AM
> To: Access Developers discussion and problem solving
> Subject: [AccessD] CurrentProject.Path syntax?
>
> ...the following two lines point to the same file ...but only line two 
> works
>
> ...what is my befuddled mind missing this time?
>
> 'MetaDraw0.LoadPicture (CurrentProject.Path & 
> "MBCC_HallC_Spring_001a.mdp"),
>
> 0, 0
> MetaDraw0.LoadPicture "v:\JISWORKING\TMS\MBCC_HallC_Spring_001a.mdp", 0, 0
>
> William
>
>
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