[AccessD] Most efficient means to retrieve most recent record

William,
I left out a key ingredient on my last post in response to this question.
After you do a seek, you have to test for a NoMatch. For example...

Rst.index = "ixStrDate"
Rst.seek "=", "20110602"
If NOT rst.nomatch then
	Do While not rst.eof
		If rst!strDate > "20110602" then
			Exit do
		End if
		<your code>
		Rst.movenext
	Loop
End If

Sorry bout dat.
Darrell
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of William Benson
(VBACreations.Com)
Sent: Thursday, June 02, 2011 5:12 PM
To: 'Access Developers discussion and problem solving'
Subject: [AccessD] Most efficient means to retrieve most recent record

Hello,

In an Access table where I import and append very similar data routinely, I
stamp every record with the same ImportTime at time of import. 

I am wondering the most efficient means of getting at the latest record
matching certain criteria?  I see three ways. 


METHOD 1
   (1) Set a recordset = the entire table ordered descending, with no WHERE
clause
    (2) use Rst.FindFirst and put the criteria here as arguments 


METHOD 2
   (1)  Use an ORDER BY (desc) clause, select all the records
     where those fields have the values I specify
   (2) Use the first record in the recordset.

METHOD 3
   (1) Select the max date where those fields have the values I specify
   (2) Select "the" record where those fields have the values I specify 
     AND
     Date = Date found from (1)   .... to me this seems unlikely to be
fastest, but who knows.

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