Dale Kalsow
dkalsow at yahoo.com
Wed May 23 13:30:40 CDT 2012
The entire field is defined as a string in the table. Also, the first time around (when the table is empty) the first record is created without an error.
________________________________
From: Rocky Smolin <rockysmolin at bchacc.com>
To: 'Access Developers discussion and problem solving' <accessd at databaseadvisors.com>
Sent: Wednesday, May 23, 2012 1:23 PM
Subject: Re: [AccessD] FindFirst Error
I think you have to put # before and after the date: strkey = "#"&
5/21/2012 & "#"
HTH
Rocky Smolin
Beach Access Software
858-259-4334
www.bchacc.com
www.e-z-mrp.com
Skype: rocky.smolin
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Dale Kalsow
Sent: Wednesday, May 23, 2012 11:14 AM
To: Access Developers discussion and problem solving
Subject: [AccessD] FindFirst Error
Good Afternoon Everyone,
I have the following code that is giving me a Run-time error '3077' Syntax
error (missing operator) in expression. on the FindFirst line. Can anyone
see why? strkey = 5/21/2012Heather Hanson
Is access not liking the space in field?
Thanks!
Set dbsDB = DBEngine(0)(0)
Set rstRS = dbsDB.OpenRecordset("tblEmployeeTimes", dbOpenDynaset)
Set rstRsNew = dbsDB.OpenRecordset("qryKeyCardImport", dbOpenDynaset)
rstRsNew.MoveFirst
Do While Not rstRsNew.EOF
strKey = Format(rstRsNew![Time], "Short Date") &
Trim(rstRsNew![Employee])
rstRS.FindFirst "[EmployeeTimesID] = " & strKey
If not rstRS.NoMatch Then
With rstRS
.Edit
rstRS![EmployeeTimesOut] = Format(rstRsNew![Time],
"Medium Time")
.Update
End With
Else
With rstRS
.AddNew
rstRS![EmployeeTimesID] = strKey
rstRS![EmployeeTimesDate] = Format(rstRsNew![Time],
"Short Date")
rstRS![[EmployeeTimesName]] = Trim(rstRsNew![Employee])
rstRS![EmployeeTimesIn] = Format(rstRsNew![Time],
"Medium Time")
.Update
End With
End If
rstRsNew.MoveNext
Loop
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