[AccessD] Create and Link Table in external database

[Rocky Smolin]

Yeah, same result. :(

r 

-----Original Message-----
From: AccessD [mailto:accessd-bounces at databaseadvisors.com] On Behalf Of
Stuart McLachlan
Sent: Tuesday, June 07, 2016 5:37 PM
To: Access Developers discussion and problem solving
Subject: Re: [AccessD] Create and Link Table in external database

Have you tried it with the DAO. back in
"Dim tdfLinked As DAO.TableDef"


On 7 Jun 2016 at 15:29, Rocky Smolin wrote:

> tdfLinked.Attributes = dbAttachedTable also generates an error 3001 
> Invalid argument. (I get enough of those on OT)
> 
> I added it before: dbFrontEnd.TableDefs.Append tdfLinked
> 
> Scoured the internets on this but no cigar.  Any other ideas?
> 
> TIA
> 
> Rocky
> 
> 
> 
> 
> -----Original Message-----
> From: AccessD [mailto:accessd-bounces at databaseadvisors.com] On Behalf 
> Of Stuart McLachlan Sent: Tuesday, June 07, 2016 3:13 PM To: Access 
> Developers discussion and problem solving Subject: Re: [AccessD] 
> Create and Link Table in external database
> 
> "If the object you're appending isn't complete ... using the Append 
> method triggers a run-time error." You have not specified any 
> Attributes.
> 
> Try adding: tdfLinked.Attributes = dbAttachedTable
> 
> --
> Stuart
> 
> On 7 Jun 2016 at 14:02, Rocky Smolin wrote:
> 
> > Dear List:
> > 
> > I am trying to create and link to a new table in an external 
> > database.
> >  The create part works fine but the linking part fails on the last
> > line: dbFrontEnd.TableDefs.Append tdfLinked, with an Error 3001 
> > Invalid argument, but I can't see why.
> > 
> > I tried changing  Dim tdfLinked As TableDef to Dim tdfLinked As 
> > DAO.TableDef but same result.  Here's the code:
> > 
> > Dim db As DAO.Database
> > Dim dbFrontEnd As DAO.Database
> > 
> > Dim wrk As DAO.Workspace
> > 
> > Dim tdf As DAO.TableDef
> > Dim tdfLinked As TableDef
> > 
> > ' Create Table
> >     Set tdf = db.CreateTableDef("tblPODetailRemarks")
> >     Set fld = tdf.CreateField("fldPODetailRemarksID", dbLong)
> >     fld.Attributes = dbAutoIncrField
> >     tdf.Fields.Append fld
> > 
> >     Set ind = tdf.CreateIndex("PrimaryKey")
> >     With ind
> >         .Fields.Append .CreateField("fldPODetailRemarksID")
> >         .Unique = False
> >         .Primary = True
> >     End With
> >     tdf.Indexes.Append ind
> > 
> >     Set fld = tdf.CreateField("fldPODetailRemarks", dbText, 255)
> >     tdf.Fields.Append fld
> > 
> >     db.TableDefs.Append tdf
> > 
> > ' Link Table    
> >     Set dbFrontEnd = CurrentDb
> >     Set tdfLinked = dbFrontEnd.CreateTableDef("tblPODetailRemarks")
> >     tdfLinked.Connect = ";Database = " & gstrDatabaseName
> >     tdfLinked.SourceTableName = "tblPODetailRemarks"
> >     dbFrontEnd.TableDefs.Append tdfLinked
> > 
> > Does anyone see what I'm doing wrong?
> > 
> > MTIA
> > 
> > Rocky Smolin
> > Beach Access Software
> > 760-683-5777
> > www.bchacc.com <http://www.bchacc.com/> www.e-z-mrp.com 
> > <http://www.e-z-mrp.com/>
> > Skype: rocky.smolin
> > 
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> > Website: http://www.databaseadvisors.com
> > 
> 
> 
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