Mark A Matte
markamatte at hotmail.com
Fri Jul 6 15:16:18 CDT 2007
Sorry Jim, Forgot to include SQL...sent to accessD also...Here is the single query approach... **************SQL*************** DELETE tblTest.Section, tblTest.code FROM tblTest WHERE (((tblTest.Section)="C1") AND ((tblTest.code) Not In (SELECT tblTest1.code FROM tblTest AS tblTest1 GROUP BY tblTest1.Section, tblTest1.code HAVING (((tblTest1.Section)="B1"));))); **************SQL*************** >From: "Mark A Matte" <markamatte at hotmail.com> >Reply-To: dba-sqlserver at databaseadvisors.com >To: dba-sqlserver at databaseadvisors.com >Subject: Re: [dba-SQLServer] Isolating matching and related records >Date: Fri, 06 Jul 2007 12:48:36 +0000 > >Jim, > >Wrote in access...syntax should be similar. I used a sub query to find ALL >Codes for Section B1...then deleted all records where section was C1 and >codes where NOT in my subquery. > >Hope it helps, > >Mark A. Matte > > > >From: Jim Lawrence <jlawrenc1 at shaw.ca> > >Reply-To: dba-sqlserver at databaseadvisors.com > >To: dba-sqlserver at databaseadvisors.com > >Subject: [dba-SQLServer] Isolating matching and related records > >Date: Thu, 05 Jul 2007 20:20:59 -0700 > > > >Hi All: > > > >The following question seems like a simple SQL question but I just can >not > >find the appropriate answer at this minute... too many long nights. > > > >Given: > > > >1. A table of many records, with each record having a couple fields >called > >{section] and [code]. > > > >2. The content of field [section] has only three possible entries of > >"A1","B1" and "C1". The contents of field [code] can be any of a variety >of > >codes. > > > >3. There will always be records for group "A1" and "C1" but not always >for > >"B1" > > > >What SQL code would find the group where there are no matching "B1" >records > >and delete all the records in the "C1" group > > > >An example of data could be; > > > >5 records of [section] = "A1", [code] = "TTR" > >4 records of [section] = "B1", [code] = "TTR" > >30 records of [section] = "C1", [code] = "TTR" > >3 records of [section] = "A1", [code] = "CYR" > >47 records of [section] = "C1", [code] = "CYR" > >5 records of [section] = "A1", [code] = "PIJ" > >4 records of [section] = "B1", [code] = "PIJ" > >30 records of [section] = "C1", [code] = "PIJ" > > > >After the SQL code was run all 47 records with [section] = "C1' and >[code] > >= > >"CYR" would be gone. > > > >It does not seem like a difficult process but... > > > >MTIA > > > >Jim > > > >_______________________________________________ > >dba-SQLServer mailing list > >dba-SQLServer at databaseadvisors.com > >http://databaseadvisors.com/mailman/listinfo/dba-sqlserver > >http://www.databaseadvisors.com > > > >_________________________________________________________________ >Local listings, incredible imagery, and driving directions - all in one >place! http://maps.live.com/?wip=69&FORM=MGAC01 > >_______________________________________________ >dba-SQLServer mailing list >dba-SQLServer at databaseadvisors.com >http://databaseadvisors.com/mailman/listinfo/dba-sqlserver >http://www.databaseadvisors.com > _________________________________________________________________ http://im.live.com/messenger/im/home/?source=hmtextlinkjuly07