Paul Nielsen
pauln at sqlserverbible.com
Thu Mar 20 08:54:50 CDT 2008
Keep it simple. you don't need to create a function for updating from a this parsing, just put the expression in your select/update statement. Update table1 Set col1 = right(t2.col2,len(t2.col2)-patindex('%[^0]%', t2.col2)+1) from table1 t1 join table2 t2 on t1.pk = t2.pk - Paul www.sqlserverbible.com -----Original Message----- From: dba-sqlserver-bounces at databaseadvisors.com [mailto:dba-sqlserver-bounces at databaseadvisors.com] On Behalf Of jwcolby Sent: Thursday, March 20, 2008 7:27 AM To: 'Discussion concerning MS SQL Server' Subject: Re: [dba-SQLServer] Diving off the deep end Right, figured that out. By "compile" I meant "parse". Now... CREATE FUNCTION StripLeadingZeros ( @StrToStrip varchar(200) ) RETURNS varchar(200) AS BEGIN -- Declare the return variable here DECLARE @strTemp varchar(200) -- Add the T-SQL statements to compute the return value here select right(@StrToStrip,len(@StrToStrip)-patindex ('%[^0]%', at StrToStrip)+1) -- Return the result of the function RETURN @strTemp END Parses correctly but returns an error: Msg 444, Level 16, State 3, Procedure StripLeadingZeros, Line 17 Select statements included within a function cannot return data to a client. So it seems that the statement: select right(@StrToStrip,len(@StrToStrip)-patindex ('%[^0]%', at StrToStrip)+1) Needs to "return" the data to a variable. However if I modify that to: @strTemp = select right(@StrToStrip,len(@StrToStrip)-patindex ('%[^0]%', at StrToStrip)+1) Then it no longer parses, returning: Msg 102, Level 15, State 1, Procedure StripLeadingZeros, Line 18 Incorrect syntax near '@strTemp'. Msg 137, Level 15, State 2, Procedure StripLeadingZeros, Line 20 Must declare the scalar variable "@strTemp". Modifying it to: @strTemp = right(@StrToStrip,len(@StrToStrip)-patindex ('%[^0]%', at StrToStrip)+1) Returns a parse error: Msg 102, Level 15, State 1, Procedure StripLeadingZeros, Line 18 Incorrect syntax near '@strTemp'. Msg 137, Level 15, State 2, Procedure StripLeadingZeros, Line 20 Must declare the scalar variable "@strTemp". I need to not only get the data out of the string, but place it in a variable and return that variable which is what I am trying to do here. John W. Colby Colby Consulting www.ColbyConsulting.com -----Original Message----- From: dba-sqlserver-bounces at databaseadvisors.com [mailto:dba-sqlserver-bounces at databaseadvisors.com] On Behalf Of Arthur Fuller Sent: Thursday, March 20, 2008 9:14 AM To: Discussion concerning MS SQL Server Subject: Re: [dba-SQLServer] Diving off the deep end First problem is the double quotes, which SQL interprets as a reference to a column. Second problem is that the statement must begin with the word SELECT. After that you're good to go: SELECT Right( 'John W. Colby', 3 ) ==> 'lby' Third issue: don't compile the query. Just run it. hth, A. On 3/20/08, jwcolby <jwcolby at colbyconsulting.com> wrote: > > I THINK THAT WE NEED TO BACK UP A FEW STEPS. > _______________________________________________ dba-SQLServer mailing list dba-SQLServer at databaseadvisors.com http://databaseadvisors.com/mailman/listinfo/dba-sqlserver http://www.databaseadvisors.com _______________________________________________ dba-SQLServer mailing list dba-SQLServer at databaseadvisors.com http://databaseadvisors.com/mailman/listinfo/dba-sqlserver http://www.databaseadvisors.com __________ NOD32 2963 (20080320) Information __________ This message was checked by NOD32 antivirus system. http://www.eset.com