Stuart McLachlan
stuart at lexacorp.com.pg
Tue Jan 15 00:21:33 CST 2013
You are trying to solve a different problem. In the problem as stated, you CAN have UP TO seven tosses, but you stop after either side has four wins, so there may anything from four to seven tries. -- Stuart On 14 Jan 2013 at 22:10, Peter Brawley wrote: > > On 2013-01-14 9:29 PM, Stuart McLachlan wrote: > > Probablilty = 0.4285714285714286 > > > > Odds = 3:4 > > > > 15 wins out of 35 possible outcomes. > > 6C4 / 2^6, ie the number of ways you can get 4 heads in 6 tries / the > total no. of possible combinations. > > PB > > > > _______________________________________________ > dba-Tech mailing list > dba-Tech at databaseadvisors.com > http://databaseadvisors.com/mailman/listinfo/dba-tech > Website: http://www.databaseadvisors.com >