Arthur Fuller
fuller.artful at gmail.com
Sun Aug 5 14:07:07 CDT 2007
Somewhere there must be a chart listing the horizontal space occupied by each of the 26 characters. Using it, you could count the occurrences of each, plus the spaces, do some addition and have a precise measurement. By the time you've got the count, though, the data in the whole report may be stale :) Regards, Arthur On 8/5/07, Steve Schapel <miscellany at mvps.org> wrote: > > Thanks, Arthur. Yes, I think that will be a solution. It's just that > the arithmetic will be a bit imprecise, as the number of available > characters depends on the relative number of W's and m's in the dat, > compared with the number of i's and l's. > > Regards > Steve > > > Arthur Fuller wrote: > > What about doing a little arithmetic on each row? Would that work? You > could > > right-justify the score, count the characters in same, then print as > many > > chars of the team name as will still fit. > -- > AccessD mailing list > AccessD at databaseadvisors.com > http://databaseadvisors.com/mailman/listinfo/accessd > Website: http://www.databaseadvisors.com >