Joe Hecht
jmhecht at earthlink.net
Sun Jun 17 11:18:51 CDT 2007
Its Joe
The code refers to "str"
If the record number is a long integer would that cause my issue and what is
the easiest way to fix it?
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Joe Hecht
Sent: Saturday, June 16, 2007 8:50 PM
To: AccessD at databaseadvisors.com
Subject: [AccessD] Hi I am back and stuck
Hi Gang,
I am back and feeling silly. Can not make combo box work.
I want to go to the record the combo selects
Private Sub Combo27_AfterUpdate()
' Find the record that matches the control.
Dim rs As Object
Set rs = Me.Recordset.Clone
rs.FindFirst "[EmpRecNum] = " & Str(Nz(Me![Combo27], 0))
If Not rs.EOF Then Me.Bookmark = rs.Bookmark
End Sub
The sql
SELECT tblEmployee.EmpRecNum, tblEmployee.EmpNumber, tblEmployee.EmpFname,
tblEmployee.EmpLName, [emplname] & ", " & [empfname] & " " & [empNumber] AS
Expr1
FROM tblEmployee
ORDER BY tblEmployee.EmpLName;
I have it so that it is showing expression one but I get
Run time error 13 on the following code line:
rs.FindFirst "[EmpRecNum] = " & Str(Nz(Me![Combo27], 0))
Please advise
Thanks
Joe
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