Joe Hecht
jmhecht at earthlink.net
Sun Jun 17 11:18:51 CDT 2007
Its Joe The code refers to "str" If the record number is a long integer would that cause my issue and what is the easiest way to fix it? -----Original Message----- From: accessd-bounces at databaseadvisors.com [mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Joe Hecht Sent: Saturday, June 16, 2007 8:50 PM To: AccessD at databaseadvisors.com Subject: [AccessD] Hi I am back and stuck Hi Gang, I am back and feeling silly. Can not make combo box work. I want to go to the record the combo selects Private Sub Combo27_AfterUpdate() ' Find the record that matches the control. Dim rs As Object Set rs = Me.Recordset.Clone rs.FindFirst "[EmpRecNum] = " & Str(Nz(Me![Combo27], 0)) If Not rs.EOF Then Me.Bookmark = rs.Bookmark End Sub The sql SELECT tblEmployee.EmpRecNum, tblEmployee.EmpNumber, tblEmployee.EmpFname, tblEmployee.EmpLName, [emplname] & ", " & [empfname] & " " & [empNumber] AS Expr1 FROM tblEmployee ORDER BY tblEmployee.EmpLName; I have it so that it is showing expression one but I get Run time error 13 on the following code line: rs.FindFirst "[EmpRecNum] = " & Str(Nz(Me![Combo27], 0)) Please advise Thanks Joe -- AccessD mailing list AccessD at databaseadvisors.com http://databaseadvisors.com/mailman/listinfo/accessd Website: http://www.databaseadvisors.com