Susan Harkins
ssharkins at setel.com
Mon Jun 25 08:48:08 CDT 2007
I came up with this one years and years ago -- will it work for you? Year(Now())-Year(date)+(DateSerial(Year(Now()),Month(date),Day(date))>Now()) Susan H. Hi Steve Sorry, it still fails miserably for, say, these dates: DOB = #2/29/1992# AtDay = #2/28/1997# returning 4 and not 5. /gustav >>> miscellany at mvps.org 23-06-2007 22:57 >>> Hehe. Answering my own question. I wouldn't mind $5 for every time I have used that expression over the last 12 years, on the assumption that I had it licked. And now I see the obvious - in the case of a 29 February birthday, evaluating age on 28 February in a non leap year works correctly, but evaluating age on 28 February during a leap year, it gives the wrong figure. So, I have modified accordingly... Age: DateDiff("yyyy",[DOB],[DateAt])+(Format([DOB]+(Format([DOB],"mmdd") =Format([DateAt],"mmdd")="0229"),"mmdd")>Format([DateAt],"mmdd")) Regards Steve Steve Schapel wrote: > However, I can't find an example where the following does not work > correctly. Can you? > > Age: > DateDiff("yyyy",[DOB],[DateAt])+(Format([DOB]+(Format([DOB],"mmdd") > ="0229"),"mmdd")>Format([DateAt],"mmdd")) -- -- AccessD mailing list AccessD at databaseadvisors.com http://databaseadvisors.com/mailman/listinfo/accessd Website: http://www.databaseadvisors.com No virus found in this incoming message. Checked by AVG Free Edition. Version: 7.5.472 / Virus Database: 269.9.1/857 - Release Date: 6/20/2007 2:18 PM