[AccessD] Age calculation

I think that is the right answer myself. A person born on 2/29/1992 is
not 5 until 3/1/1997. On 2/28/1997 they are still 4 aren't they?

GK

On 6/25/07, Gustav Brock <Gustav at cactus.dk> wrote:
> Hi Steve
>
> Sorry, it still fails miserably for, say, these dates:
>
> DOB = #2/29/1992#
> AtDay = #2/28/1997#
>
> returning 4 and not 5.
>
> /gustav
>
> >>> miscellany at mvps.org 23-06-2007 22:57 >>>
> Hehe.  Answering my own question.  I wouldn't mind $5 for every time I
> have used that expression over the last 12 years, on the assumption that
> I had it licked.
>
> And now I see the obvious - in the case of a 29 February birthday,
> evaluating age on 28 February in a non leap year works correctly, but
> evaluating age on 28 February during a leap year, it gives the wrong figure.
>
> So, I have modified accordingly...
>
> Age: DateDiff("yyyy",[DOB],[DateAt])+(Format([DOB]+(Format([DOB],"mmdd")
> =Format([DateAt],"mmdd")="0229"),"mmdd")>Format([DateAt],"mmdd"))
>
> Regards
> Steve
>
>
> Steve Schapel wrote:
> > However, I can't find an example where the following does not work
> > correctly.  Can you?
> >
> > Age: DateDiff("yyyy",[DOB],[DateAt])+(Format([DOB]+(Format([DOB],"mmdd")
> > ="0229"),"mmdd")>Format([DateAt],"mmdd"))
> --
>
>
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-- 
Gary Kjos
garykjos at gmail.com