[AccessD] Age calculation

I think leaplings should not celebrate their birthdays on March 1 because:

format("date to celebrate birthday","m") should equal to
format("birthdate","m")

Billy

On 6/25/07, Gary Kjos <garykjos at gmail.com> wrote:
>
> I see. The search I did said that "most celebrate it on either
> February 28 or March 1". Good luck. Glad I don't have to worry about
> it. At least not at the moment.
>
> :-)
>
> GK
>
> On 6/25/07, Gustav Brock <Gustav at cactus.dk> wrote:
> > Hi Gary
> >
> > Some are (they decide for themselves when to celebrate it, many use the
> following weekend) but most if not all European public authorities and date
> or age sensitive corporations like insurance companies rely on the common
> sense rules of "last day of February" or "if your birthday is a day of
> February, it will never fall in any other month than February".
> > Taiwan also follows this rule:
> >
> > http://en.wikipedia.org/wiki/Leap_year
> >
> > Browse to the bottom and read about these "leaplings" ...
> >
> > /gustav
> >
> > >>> garykjos at gmail.com 25-06-2007 16:17 >>>
> > I think that is the right answer myself. A person born on 2/29/1992 is
> > not 5 until 3/1/1997. On 2/28/1997 they are still 4 aren't they?
> >
> > GK
> >
> > On 6/25/07, Gustav Brock <Gustav at cactus.dk> wrote:
> > > Hi Steve
> > >
> > > Sorry, it still fails miserably for, say, these dates:
> > >
> > > DOB = #2/29/1992#
> > > AtDay = #2/28/1997#
> > >
> > > returning 4 and not 5.
> > >
> > > /gustav
> > >
> > > >>> miscellany at mvps.org 23-06-2007 22:57 >>>
> > > Hehe.  Answering my own question.  I wouldn't mind $5 for every time I
> > > have used that expression over the last 12 years, on the assumption
> that
> > > I had it licked.
> > >
> > > And now I see the obvious - in the case of a 29 February birthday,
> > > evaluating age on 28 February in a non leap year works correctly, but
> > > evaluating age on 28 February during a leap year, it gives the wrong
> figure.
> > >
> > > So, I have modified accordingly...
> > >
> > > Age:
> DateDiff("yyyy",[DOB],[DateAt])+(Format([DOB]+(Format([DOB],"mmdd")
> > > =Format([DateAt],"mmdd")="0229"),"mmdd")>Format([DateAt],"mmdd"))
> > >
> > > Regards
> > > Steve
> > >
> > >
> > > Steve Schapel wrote:
> > > > However, I can't find an example where the following does not work
> > > > correctly.  Can you?
> > > >
> > > > Age:
> DateDiff("yyyy",[DOB],[DateAt])+(Format([DOB]+(Format([DOB],"mmdd")
> > > > ="0229"),"mmdd")>Format([DateAt],"mmdd"))
> > > --
> >
> >
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> > Website: http://www.databaseadvisors.com
> >
>
>
> --
> Gary Kjos
> garykjos at gmail.com
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>



-- 
Billy Pang
http://dbnotes.blogspot.com/
"Once the game is over, the King and the pawn go back in the same box." -
Italian proverb