Gustav Brock
Gustav at cactus.dk
Sun Mar 23 04:17:43 CDT 2008
Hi John As for the wide spacing you could do: Public Function aTest(strA As String) As String Dim abytTest() As Byte Dim intChar As Integer Dim strOut As String abytTest = strA For intChar = LBound(abytTest) To UBound(abytTest) If abytTest(intChar) = 0 Then strOut = strOut & Space(1) Else strOut = strOut & Chr(abytTest(intChar)) End If Next aTest = RTrim(strOut) End Function But it isn't much simpler than using Mid: Public Function StringWide(strPrint As String) As String Dim strWide As String Dim intLen As Integer Dim intPos As Integer intLen = Len(strPrint) If intLen > 0 Then strWide = Space(intLen * 2 - 1) End If For intPos = 1 To intLen Mid(strWide, intPos * 2 - 1) = Mid(strPrint, intPos, 1) Next StringWide = strWide End Function /gustav >>> jwcolby at colbyconsulting.com 22-03-2008 22:57 >>> Well yea. Uhh... sure. I thought I was asking a syntax question. Given strCompanyName Colby Consulting I need an array of: C o l b y C o n s u l t i n g It is exactly that piece that I do not know how to do elegantly. Oh sure I can do the Mid() function N times but that is inelegant. I thought perhaps there would be a single SomeKeyWord(strCompanyName) that would return an array of the characters in the strCompanyName. I really don't work with arrays that much and so I am much less godly in that area. John W. Colby Colby Consulting www.ColbyConsulting.com