Denis Sherman
max.wanadoo at gmail.com
Tue Feb 17 12:42:58 CST 2009
Stuart,
What sort of thing would you use this for? Would it be to archive stuff,
mail stuff, that sort of thing? Or is there something more intrinsic to
Access that I am not grasping?
Thanks
Max
-----Original Message-----
From: accessd-bounces at databaseadvisors.com
[mailto:accessd-bounces at databaseadvisors.com] On Behalf Of Stuart McLachlan
Sent: 17 February 2009 14:46
To: Access Developers discussion and problem solving
Subject: [AccessD] ZIpping Files
There has just been a discussion over on dba-Tech about the built in Zip
capabilities in
Windows (XP onwards?) where "Compressed (zipped) Folders" are just ordinary
zip files.
This got me thinking about how you could use the built in capabilities to
manage zip files
through VBA rather than needing a third party DLL, the Winzip CLI or
whatever.
Turns out it is trivial to to create an empty ZIp file, it is just a string
of 22 bytes as follows:
Function CreateNewZipFolder(Filename As String) As Long
Dim strEmptyZip As String
strEmptyZip = Chr$(80) & Chr$(75) & Chr$(5) & Chr$(6) & String$(18, Chr$(0))
Open Filename For Binary As #1
Put #1, , strEmptyZip
Close #1
End Function
You can now use a Shell.Application object to work with this file/folder.
Firstly set a reference to Microsoft Shell Controls and Automation:
Shell32.dll
Then you just need a couple of simple functions:
Function AddFileToZip(ZipFileName As String, Filename As String)
'Zipfilename and Filename need to be full paths
Dim oShellApp As Shell32.Shell
Set oShellApp = CreateObject("Shell.Application")
oShellApp.NameSpace(ZipFileName).CopyHere Filename
Set oShellApp = Nothing
End Function
and
Function ExtractFileFromZip(ZipFileName As String, DestDir as
String,Filename As String)
'Zipfilename and DestDir need to be full paths
'Filename should just be the filename without a path
Dim oShellApp As Shell32.Shell
Set oShellApp = CreateObject("Shell.Application")
oShellApp.NameSpace(DestDir).CopyHere _
oShellApp.Namespace(ZipFileName).Items.Item(Filename)
Set oShellApp = Nothing
End Function
To extract all files replace
oShellApp.Namespace(ZipFileName).Items.Item(Filename)
with
oShellApp.Namespace(ZipFileName).Items
Note that this is a bare shell and you will need to add a bit of error
checking - oShellApp
doesn't like it if files/directories don't exist and will pop up a standard
"File exists, do you
want to copy" dialog if the zip or destination already contains the file.
--
Stuart
--
AccessD mailing list
AccessD at databaseadvisors.com
http://databaseadvisors.com/mailman/listinfo/accessd
Website: http://www.databaseadvisors.com