Stuart McLachlan
stuart at lexacorp.com.pg
Thu Nov 3 17:35:46 CDT 2011
No typos, he wants the number of Unique patients having the same Uitv and Sub. A ee has three records, A ee 101 A ee 101 A ee 102 but two unique patients, 101 and 102. Hence: A ee 2 Similary B ee has two unique patients 201 and 301, hence: B ee 2 -- Stuart On 3 Nov 2011 at 23:25, Asger Blond wrote: > Pedro, > I don't understand your example with the data provided. Could you > please tell if you made some typos - especially: Why is the data "A ee > 102" not listed or counted in the result, and why is the data "B ee > 201" and "B ee 301" listed as a count of 2 in the result? IOW: What's > defining a unique entity for the counting in your example: Uitv + Sub > or Uitv + Sub + Patient? Asger > > -----Oprindelig meddelelse----- > Fra: accessd-bounces at databaseadvisors.com > [mailto:accessd-bounces at databaseadvisors.com] På vegne af > pedro at plex.nl Sendt: 3. november 2011 09:44 Til: > accessd at databaseadvisors.com Emne: [AccessD] unique patients > > Dear Group, > > how can i query the unique patients, from "Uitv" and "Sub". > > Data > > Uitv Sub Patient > A ee 101 > A ee 101 > A ee 102 > A ff 201 > A gg 301 > B ee 201 > B ee 301 > B hh 501 > > > > Result > > Uitv Sub Unique Patient > A ee 2 > A ff 1 > A gg 1 > B ee 2 > B hh 1 > > > Thanks > > Pedro Janssen > > -- > AccessD mailing list > AccessD at databaseadvisors.com > http://databaseadvisors.com/mailman/listinfo/accessd > Website: http://www.databaseadvisors.com > > > -- > AccessD mailing list > AccessD at databaseadvisors.com > http://databaseadvisors.com/mailman/listinfo/accessd > Website: http://www.databaseadvisors.com