[AccessD] unique patients

I see - thanks Stuart.
Asger

-----Oprindelig meddelelse-----
Fra: accessd-bounces at databaseadvisors.com [mailto:accessd-bounces at databaseadvisors.com] På vegne af Stuart McLachlan
Sendt: 3. november 2011 23:36
Til: Access Developers discussion and problem solving
Emne: Re: [AccessD] unique patients

No typos,  he wants the number of Unique patients having the same Uitv and Sub.

A ee  has three records, 

A ee 101
A ee 101
A ee 102

but two unique patients, 101 and 102.

Hence: 
A ee 2

Similary B ee has two unique patients 201 and 301, hence:

B ee 2

-- 
Stuart

On 3 Nov 2011 at 23:25, Asger Blond wrote:

> Pedro,
> I don't understand your example with the data provided. Could you
> please tell if you made some typos - especially: Why is the data "A ee
> 102" not listed or counted in the result, and why is the data "B ee
> 201" and "B ee 301" listed as a count of 2 in the result? IOW: What's
> defining a unique entity for the counting in your example: Uitv + Sub
> or Uitv + Sub + Patient? Asger
> 
> -----Oprindelig meddelelse-----
> Fra: accessd-bounces at databaseadvisors.com
> [mailto:accessd-bounces at databaseadvisors.com] På vegne af
> pedro at plex.nl Sendt: 3. november 2011 09:44 Til:
> accessd at databaseadvisors.com Emne: [AccessD] unique patients
> 
> Dear Group,
> 
> how can i query the unique patients, from "Uitv" and "Sub". 
> 
> Data		
> 
> Uitv	Sub	Patient
> A	ee	101
> A	ee	101
> A	ee	102
> A	ff	201
> A	gg	301
> B	ee	201
> B	ee	301
> B	hh	501
> 
> 
> 
> Result		
> 
> Uitv	Sub	Unique Patient
> A	ee        2
> A	ff	  1
> A	gg	  1
> B	ee	  2
> B	hh	  1
> 
> 
> Thanks
> 
> Pedro Janssen
> 
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> 
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